Question

In triangle PQR , If PE-4cm, QE=4.5cm PF=8cm, RF=0.36cm. State whether EF II QR?​

Answer 1

Answer:

I aint sure

Bro mark

Ok

Thx

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm

\frac{PE}{EQ}=\frac{4}{4.5}=\frac{8}{9}\, cm                       and               \frac{PF}{FR}=\frac{8}{9}\, cm

 

We have  

               \frac{PE}{EQ} = \frac{PF}{FR}

Hence, EF is parallel to QR.