in triangle pqr, if pq=10cm and angleprq=90°,anglepqr=30°then find QR
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[math]S[/math] is the midpoint of the hypotenuse [math]PR.[/math]
With [math]S[/math] as centre, draw a circle with radius equal to [math]PS.[/math] Obviously, this circle will pass through points [math]P[/math] and [math]R.[/math]
[math]\angle PQR = 90^o.[/math]
[math]\Rightarrow \quad[/math] The circle will also pass through point [math]Q[/math] since [math]PR[/math] is a diameter of the circle and the measure of the angle subtended by the diameter on the circle is equal to [math]90^o.[/math]
[math]\Rightarrow \qquad SQ[/math] is a radius of the circle.
[math]\Rightarrow \qquad QS = PS = 5[/math] cm.
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