Question

In triangle PQR, if PR + QR = 25 cm and PQ = 5cm. Then the value of sin P . tan P is​

Answer 1

Answer:

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Step-by-step explanation:

Let length PR be X and QR be Y, using pythagoras theorem,

5^2 + (25 — X)^2 = X^2,

25 + 625 — 50X + X^2 = X^2

X^2 — X^2 +50X = 650, 50X = 650, X = 650/50,

X = 13, Y = 25 — 13, Y = 12. Therefore length PR is 13 cm and QR is 12 cm.

SinP =QR/PR, SinP = 12/13, SinP = 0.923077

<P = Sin(-1)0.923077, <P = 67.38°

CosP = PQ/PR, CosP = 5/13, CosP = 0.384615

TanP = QR/PQ, TanP = 12/5, TanP = 2.4

<R = 180 — 90 — 67.38, <R = 22.62°