Question

in triangle PQR,is ST is
parallel
QR & PS = 2cm,
SQ= 3cm, PT =3cm then find
PR.​

Answer 1

Answer:

In ΔPQR and ΔPQR

angle PST = angle PST { corresponding angles}

angle p = angle p {common}

using AA similar condition

angle PST ~ angle PQR

ar ΔPQR / ar ΔPST = PQ² / PS²

... ar {ΔPQR} / ar {ΔPST} = [PS + SQ]² / PS²

= [3+2]² / 3²

= 5² / 3²

... = 25 /9

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