Question

In triangle pqr ,l(pq)=12cm,(qr)=5cm,find hypotenuse pr.

Answer 1

In ΔPQR

(PR)

2

=(PQ)

2

+(QR)

2

(PR)

2

=(12)

2

+(5)

2

(PR)

2

=169

PR=13

Now AOBQ is a square

So, QB=x

Then, BR=5−x

Similarly AQ=x

Then AP=12−x

Also, CR=BR

CR=5−x

[∵ Length of tangents drawn from external point are equal]

And, CP=AP=12−x

[∵ Length of tangents drawn from external point are equal]

PR=PC+CR

13=5−x+12−x

2x=4⇒x=2 cm.

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