In triangle PQR , m < PQR = 90 degrees , seg QS is perpendicular to seg PR, PS = 10 , SR = 8 , Find PQ, QS, QR.
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Step-by-step explanation:
we know that in a right angle triangle perpendicular segments to the hypotenuse from the opposite vertex, s into geometric mean of the segment into which hypotenuse is divided
Here,seg PM perpendicular seg QR
:PM2= QM×MR
(10)2 = 8×MR
100 = 8 ×MR
100/8 = MR
25/2= MR
Now,
QR=QM×MR
8=25/2
16+25/2
41/2
20.5 = QR
hence proof : QR =20.5
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