Math, asked by shahdab2005lm10, 7 months ago

In triangle PQR ​∠​ P:​ ∠​ Q:​ ∠​ R=3:2:1 and PQ​║RD. Find measure of ​∠ERD

Answers

Answered by Liyutsararename
3

Answer:

Step-by-step explanation:

angle P : angle Q : angle R = 3:2:1

angle P = 3x

angle Q = 2x

angle R = 1x

we all know that sum of interior angles of a triangle is 180°.

angle P + angle Q + angle R = 180°.

3x+2x+1x = 180°.

6x = 180°

x = 180/6

x = 30°.

angle P = 3x = 3 x 30° = 90°

angle Q = 2x = 2 x 30° = 60°

angle R = 1x = 1 x 30° = 30°

according to the given data of angles the figure will be like this given in the attachment below-REFER THE FIRST FIGURE FOR THE ANGLES!

now , to find angle ERD

As PQ // RD

[FOR PQ//RD - REFER THE SECOND FIGURE WHICH I HAVE GIVEN IN THE ATTACHMENT BELOW!  

angle DRQ = angle PQR(alternate interior angles)

as angle PQR = 60°

angle DRQ = 60° [as angle DRQ = angle PQR]

angle PRQ = 30° [find above]

angle ERP = angle DRQ = 60° [ BECAUSE PQ // RD]

so angle PRQ = 30°

angle ERD(when it is not a straight line)

= angle PRQ + angle ERP + angle DRQ

= 30° + 60° + 60°

= 150°

so the measure of angle ERD = 150°

(which is not a straight line)

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