In triangle PQR p-r=42 q-r=21 find angles p q r
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Answered by
6
p+q+r=180
(42+r)+(21+r)+r=180
63+3r=180
r=39
p=42+39=81
q=21+39=60
(42+r)+(21+r)+r=180
63+3r=180
r=39
p=42+39=81
q=21+39=60
Answered by
5
p-r=42
p=42+r
q-r=21
q=21+r
we know that sum of angle of triangle is 180
p+q+r=180
(42+r)+(21+r)+r=180
63+3r=18
3r=180-63
r=117 /3
r=39
hence p=42+r
p=42+39
p=81
q=21+r
q=21+39
q=60
hope it will helpful...
And be brainly.....
p=42+r
q-r=21
q=21+r
we know that sum of angle of triangle is 180
p+q+r=180
(42+r)+(21+r)+r=180
63+3r=18
3r=180-63
r=117 /3
r=39
hence p=42+r
p=42+39
p=81
q=21+r
q=21+39
q=60
hope it will helpful...
And be brainly.....
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