Question

In triangle PQR,PD is perpendicular to QR,such that D lies on QR. If PQ=a,PR=b,QD=c and DR=d,prove that (a+b)(a-b)=(c+d)(c-d)​

Answer 1

Step-by-step explanation:

Given In A PQR, PD 1 QR, PQ = a, PR = b,QD = c and DR =d

To prove (a + b) (a-b) = (c + d)(c-d)

Proof In right angled ΔPDQ,