Question

In triangle PQR PQ=5cm, QR=6cm and RP=8.2cm
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Answer 1

Answer:

Construction of triangle PQR and its circumcircle:

Draw a line segment RP = 8.2 cm.

With P as center and a radius of 5 cm, draw an arc.

With Q as center and a radius of 6 cm, draw an arc cutting the previous arc.

Name the point of intersection of these two arcs as Q.

PQR is the required triangle.

With R as center and a radius of more than half of PR, draw arcs on either side of PR.

With the same radius and P as center cut these arcs.

Join the points of intersection of these arcs.

Repeat the same steps for side PQ.

The perpendicular bisectors of these two sides meet at a point O.

With O as center and OR as center, draw a circle passing through P, Q and R.

This is the circumcircle of triangle PQR.

Step-by-step explanation:

Answer 2

Answer:

triangle PQR PQ=5cm, QR=6cm and RP=8.2cm

thanks poulami