Question

in triangle PQR, PQ is 4cm, PR is 8cm and RT is 6cm. find (1) the area of triangle PQR (2) the length of QS

Answer 1

PR=8
PQ=4
RT=6
base ×altitude = base × altitude
PR×QS = PQ × RT
8×QS=4×6
QS=3cm
PQR=1/2×base×altitude
=1/2×8×3
4×3=12cm²

Answer 2

Answer:

Area is 12 square centimeter and QS is 3 cm

Step-by-step explanation:

Given In triangle PQR,

PQ = 4cm, PR = 8cm, RT = 6cm.

we have to find the area of PQR and the length of QS

$\text{Area of triangle PQR }=\frac{1}{2}\times RT\times PQ$

                                       =  $\frac{1}{2}\times 6\times 4=12cm^2$

Also in triangle PQR, RT and QS are perpendiculars on the bases PQ and PR respectively.

⇒ $\frac{1}{2}\times PQ\times RT=\frac{1}{2}\times PR\times QS$

⇒ PQ×RT = PR × QS

⇒ 4×6=8×QS

⇒ QS=3cm