in triangle PQR ,PQ is parallel to PR and angle PRS is 135. find the angle P
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Answer:
67.5°
Step-by-step explanation:
Given:
PQ || PR
PQ || PR∠PRS = 135°
To find:
We have to find ∠P
Solution:
Exterior angle of ∆PQR
135° = Exterior angle ∠PRS
Let us consume ∠PQR = x°
Let us consume ∠QPR = x°
Exterior angle = Sum of opposite interior angle
∠PRS = ∠PQR + ∠QPR
135° = x° + x°
135° = 2x°
135 / 2 = x°
67.5° = x°
∠QPR = 67.5°
∠ P = 67.5°
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