In triangle PQR,PQ=PR and QL=MR. prove PL=PM
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given PQR, PQ=PR,QL=MR
proof :
PQ,=PR(given)
QL=MR(given)
Angle P=Angle P(common side)
there fore PL=PM..
proof :
PQ,=PR(given)
QL=MR(given)
Angle P=Angle P(common side)
there fore PL=PM..
Swapnil11111:
i think it is wrong
Answered by
6
proof
draw a line PS from P to the mid of LM.
SQ=SR(construction)
PQ=PR(given)
<QPS=<SPR
triangle PQS congruent to triangle PRS
Therefore <Q=<R(CPCT)
IN TRIANGLE PSQ AND PSR
PQ=PR(GIVEN)
<Q=<R(CPCT)
QL=MR
TR PQL CON PMR
PL=PM(CPCT)
draw a line PS from P to the mid of LM.
SQ=SR(construction)
PQ=PR(given)
<QPS=<SPR
triangle PQS congruent to triangle PRS
Therefore <Q=<R(CPCT)
IN TRIANGLE PSQ AND PSR
PQ=PR(GIVEN)
<Q=<R(CPCT)
QL=MR
TR PQL CON PMR
PL=PM(CPCT)
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