In triangle PQR,PQ=PR and S is a point on pq such that ps=sr=qr . Find the value of angle QPR.
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Given AB is 3 cm,PR is 2 cm PR is 6 cm
In △PAB and △PQR
∠PAB=∠PQR (corresponding angles)
and ∠P is common.
∴△PAB∼△PQR (AA similarity criterion)
Since corresponding sides are proportional,
QR
AB
=
PR
PB
QR=
PB
AB×PR
=
2
3×6
Thus, QR=9 cm.
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