In triangle pqr, pq = pr, angle p = 50 degrees. find angle q and angle r
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In △PQR,∠PQR=90∘
BY Pythagoras theorem,
PR2=PQ2+QR2
⇒(5)2=PQ2+(4)2
⇒(5)2−(4)2=PQ2
⇒PQ2=25−16
⇒PQ2=9
⇒PQ=9
⇒PQ=3
tanR=QRPQ=43.
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