Question

In triangle PQR, PQ=PR,<P=52°,<Q=?,<R=?​

Answer 1

Answer:

angle q=64,angle p=64

Step-by-step explanation:

<p+<q+<r=180°

52°+angle q+angle p=180°

angle q+angle p=180-52

2<p=128 (since, angle q=angle p)

<p=128/2

<p=64

then,<q=64

therefore,<q and <r =64

Answer 2

hope it helps

angles opposite to equal sides are equal