Question

In triangle pqr,pq=qr and angle q=40 then find angle p

Answer 1

angles opposite to equal sides are equal so angle P= angle R = x(say)
40+x+x=180°(angle sum prop)
2x= 140
x=70°
so angle P = 70°

Answer 2

∠p = 70° if In triangle pqr,pq=qr and angle q=40

Step-by-step explanation:

in Δ pqr

pq = pr

=> Triangle is isosceles

=> ∠ p = ∠r

∠ p + ∠q +  ∠r = 180°  (sum of angles of triangle)

∠q = 40° given

=>  ∠ p + 40°+  ∠r = 180°

=>  ∠ p +  ∠r = 140°

∠ p = ∠r

=> ∠ p +  ∠p = 140°

=> 2∠p = 140°

=> ∠p = 70°

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