Question

in triangle pqr, pq=qr,p=x+10 and q=4x-5 then find each of the angles of pqr

Answer 1

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angles opposite to equal sides are equal so angle P= angle R = x(say)

40+x+x=180°(angle sum prop)

2x= 140

x=70°

so angle P = 70°

Answer 2

Answer:

given:-

pqr is a triangle such that PQ = PR angle P = X + 10 and angle Q = 4 - 5

to find :- angle p, angle q, angle r

Step-by-step explanation:

in triangle pqr PQ = PR

we can say that it is a isosceles triangle

angle Q = angle p ..... eq1

now we know that

angle P + angle Q + angle R = 180 ......(linear pair)

x+10+4x-5+4x-5=180.......(from eq1)

9x+10-10=180

x=180/9

x=20

angle p =x+10= 20+10=30

angleq=4x-5=80-5=75

angle r=4x-5=75