Question

in triangle pqr , pqr90 degree, PQ - 7 km,
QR - 24 km. Sketch triangle PQR and use
Pythagoras' rule to calculare PR.​

Answer 1

✬ PR = 25 km ✬

Step-by-step explanation:

Given:

• A right angled ∆PQR.
• Length of PQ , QR is 7 and 24 km respectively.
• Triangle is right angled at R.

To Find:

• What is the length of PR ?

Solution: Let the length of PR be x km. In ∆PQR we have

• PQ = 7 km {perpendicular}

• QR = 24 km {base}

• PR = x km {hypotenuse}

• ∠PQR = 90°

Applying Pythagoras Theorem in ∆PQR

★ H² = Perpendicular² + Base² ★

$\implies{\rm }$ PR² = PQ² + QR²

$\implies{\rm }$ x² = 7² + 24²

$\implies{\rm }$ x² = 49 + 576

$\implies{\rm }$ x = √625

$\implies{\rm }$ x = 25

Hence, the length of PR is 25 km.

Answer 2

Answer:

Given :-

in triangle pqr , pqr90 degree, PQ - 7 km,

QR - 24 km

To Find :-

PR

Solution :-

At first

We know that

H² = P² + B²

PR² = PQ² + QR²

PR² = (7)² + (24)²

PR² = 49 + 576

PR² = 625

PR = √625

PR = 25