Question

In triangle pqr pr= 10 CM qr= 4 CM, and PL= 6cm find the area of pqr

Answer 1

Area of Δ PQR = 12 cm²

Step-by-step explanation:

PR = 10 cm

QR = 4 cm

PL = 6 cm

LR² = PR² - PL²

=> LR² = 10² - 6²

=> LR = 8

Area of Δ PLR = (1/2) & PL * LR = (1/2) * 6 * 8 = 24 cm²

QR = 4 cm

LQ = LR - QR = 8 - 4 = 4 cm

Area of Δ PLQ = (1/2) & PL * LQ = (1/2) * 6 * 4 = 12 cm²

Area of Δ PQR = Area of Δ PLR  - Area of Δ PLQ  = 24 - 12 =12 cm²

Area of Δ PQR = 8 cm²

Area of Δ PQR =  (1/2)* PR * QM  = (1/2) * 10 * QM = 12

=> QM = 2.4 cm

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Answer 2

Answer:

here is your answer mate...

Step-by-step explanation:

find the value of LR

PL²+LR²=PR²

5² +LR² =8²

LR =√64-25

LR. =√39

LR=6.24cm

now,

LQ=6.24-4=2.24cm

in triangle PLQ

PL²+LQ²=PQ²

5²+2.24²=PQ²

25+5.01=PQ²

PQ=5.47cm

Area of triangle( PLR)=1/2×B×H

=1/2×6.24×5

=15.6 cm²

Area of triangle(PLQ)=1/2×B×H

=1/2×2.24×5

=5.6 cm²

area of ∆PQR=15.6-5.6

=10 cm²

1/2×8×QM=10

QM=10/4

QM=2.5 cm

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