Question

In triangle PQR,PR=10cm, QR=4 cm and PL=6cm. (A) Find the area of the triangle PQR.

Answer 1

$\huge \boxed{ \texttt {\fcolorbox{red}{aqua}{hii \: mate}}}$


$\huge \mathfrak{here's \: ur \: answer}$


There are two formulas to find the area of triangle:-
they are
$\frac{1}{2} \times base \times height$

$\sqrt{s(s - a)( s- b)(s - c)}$



In your question I am applying the second formula since the height is not given


$semi \: perimeter,s = \: \frac{10 + 4 + 6}{2} \\ \\ = \frac{20}{2} \\ \\ = 10$


a = 10
b = 4
c = 6

follow the attachment above ⏫⏫


$\huge \bold{ANSWER = 8 {cm}^{2} }$



$\mathbb{HOPE \: IT \: HELPS \: U}$

Answer 2

So, Area of  $\bigtriangleup PQR$ is $12cm^{2}$

Step-by-step explanation:

Given,

For a $\bigtriangleup PQR$ whose $PR=10cm$,$QR=4cm$ and $PL=6cm$ where $PL\perp QR$

We have the formula to find the area of triangle,

$=\frac{1}{2}\times base \times height$

Where,

$Base=QR=4cm$ and $Height=PL=6cm$

∴ Area of triangle$=\frac{1}{2}\times 4\times 6$

⇒Area of triangle$=12cm^{2}$

∴ Area of  $\bigtriangleup PQR$ is $12cm^{2}$