Question

In triangle PQR, PR = 8cm, QR = 4 cm and PL = 5cm. Find (i) the area of triangle PQR (ii) QM

Answer 1

find the value of LR

PL²+LR²=PR²

5² +LR² =8²

LR =√64-25

LR. =√39

LR=6.24cm

now,

LQ=6.24-4=2.24cm

in triangle PLQ

PL²+LQ²=PQ²

5²+2.24²=PQ²

25+5.01=PQ²

PQ=5.47cm

Area of triangle( PLR)=1/2×B×H

=1/2×6.24×5

=15.6 cm²

Area of triangle(PLQ)=1/2×B×H

=1/2×2.24×5

=5.6 cm²

area of ∆PQR=15.6-5.6

=10 cm²

1/2×8×QM=10

QM=10/4

QM=2.5 cm

Answer 2

Answer:

$\huge\mathfrak{\underline{\underline{\red{Answer:-}}}}$

find the value of LR

• PL²+LR²=PR²
• 5² +LR² =8²
• LR =√64-25
• LR. =√39
• LR=6.24cm

now,

• LQ=6.24-4=2.24cm

in triangle PLQ

• PL²+LQ²=PQ²
• 5²+2.24²=PQ²
• 25+5.01=PQ²
• PQ=5.47cm

Area of triangle( PLR)=1/2×B×H

=1/2×6.24×5

=15.6 cm²

Area of triangle(PLQ)=1/2×B×H

=1/2×2.24×5

=5.6 cm²

area of ∆PQR=15.6-5.6

=10 cm²

• 1/2×8×QM=10

• QM=10/4

• QM=2.5 cm

Thanks!!