in triangle pqr PR equal to 10 cm QR equal to 4 cm and PL call to 6 cm find the area of triangle pqr
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Area of Δ PQR = 12 cm²
Step-by-step explanation:
PR = 10 cm
QR = 4 cm
PL = 6 cm
LR² = PR² - PL²
=> LR² = 10² - 6²
=> LR = 8
Area of Δ PLR = (1/2) & PL * LR = (1/2) * 6 * 8 = 24 cm²
QR = 4 cm
LQ = LR - QR = 8 - 4 = 4 cm
Area of Δ PLQ = (1/2) & PL * LQ = (1/2) * 6 * 4 = 12 cm²
Area of Δ PQR = Area of Δ PLR - Area of Δ PLQ = 24 - 12 =12 cm²
Area of Δ PQR = 8 cm²
Area of Δ PQR = (1/2)* PR * QM = (1/2) * 10 * QM = 12
=> QM = 2.4 cm
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