Question

In triangle PQR, PS is perpendicular to QR.
If PS = 6 cm, find the length of QR.
Pls answer correctly​

Answer 1

Step-by-step explanation:

IN ∆ PSQ

PS = 6 CM

ANGLE PQS = 60°

TAN 60 ° = PS / QS

√3 = 6 / QS

√3 QS = 6

QS = 6/√3

= 6/√3 × √3/ √3

= 6√3 / 3

= 2√3 CM

NOW , IN ∆PSR

TAN 30° = PS / SR

1 / √3 = 6 / SR

HENCE , SR = 6 √ 3

LENGTH OF QR = QS + SR

= 2 √ 3 + 6 √ 3

= 8 √3 ANSWER

Answer 2

Answer:

8√3cm.

Step-by-step explanation:

Given, PQ⊥QR,

           PS = 6cm

    tan 60° = perpendicular/base

    ⇒√3=6/QS

            =6/√3 = 2√3 cm.

    tan 30° = 6/SR

    ⇒1/√3 = 6/SR

    ⇒SR= 6√3 cm

∴QS+SR = QR

 ⇒QR = 2√3 + 6√3

           = 8√3 cm.