Question

In triangle pqr q =90 12cosp = 5sinp than find pr
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Answer 1

Answer:

pr=13

Step-by-step explanation:

given

angle q=90°

12cosp=5sinp

sinp÷cosp=12÷5

tanp = 12÷5 then

pq=5 and qr = 12

by pythgoras therom

${5}^{2} + {12}^{2} = {pr}^{2}$

$144 + 25 = pr ^{2}$

$169 = {pr}^{2}$

$\sqrt{169} = pr$

$pr = 13$