Question

in triangle PQR,QR=4.2 cm, angle Q=30°,PQ+PR=8.5 construct triangle PQR​​

Answer 1

$\huge \tt \color{skyblue} \: \star \: answer \: \star$

Triangle is in the attachment.

Steps of constructions:

(1) Draw seg QR of length 4.2 cm.

(2) Draw ray QT such that ∠RQT = 40°.

(3) Mark point S on ray QT such that QS = 8.5 cm

(4) Draw seg RS.

(5) Construct the perpendicular bisector of seg RS .

(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.

(7) Draw seg PR.

Therefore, △ABC is the required triangle