In triangle PQR, QT= TR, PS is perpendicular to QR, then what do you name PT and PS.
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Answer:
In △s PTR and PTQ
∠PTR=∠PTQ (each 90∘)
PQ=PR (Given)
PT=PT (Common side)
Thus, △PTR≅△PTQ
Hence, TR = TQ (By CPCT)
Step-by-step explanation:
I hope it's help you
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