in triangle PQR QT=TR PS perpendicular to QR what do you name PT and PS
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Answer:
In △s PTR and PTQ
∠PTR=∠PTQ (each 90
∘
)
PQ=PR (Given)
PT=PT (Common side)
Thus, △PTR≅△PTQ
Hence, ∠TPR=∠TPQ (By CPCT)
or, PT bisects ∠QPR
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