Question

in triangle PQR R=0.72 P=1.14 angle Q=94.6° find q​

Answer 1

Step-by-step explanation:

PQ=6.2cm, ∠Q=60

∘

& RQ-PR=3cm

1)Draw PQ of length 6.2cm.

2)Draw ∠Q=60

∘

.Let the ray be QX.

3)Open the compass to length RQ-PR=3cm.

Since RQ-PR=3cm;

(RQ-PR) is negative

From point Q as centre, cut an arc on ray QX let the arc interect QX at D.

4)Join PD.

5)Now draw perpendicular bisector of PD.

6)Join PR; △ABC is the required △le.