Question

in triangle pqr righgt angled at Q PQ=3cm and PR=6cm determimne angle Pand angleR​

Answer 1

Refers to attachement.

Answer 2

Answer:

Given: PQ = 3cm

PR = 6cm

$Therefore,\frac{PQ}{PR} = sin R \\ \\ </p><p>sin R = \frac{3}{6} = \frac{1}{2} \\ \\ \angle {PRQ}=30°</p><p>\\ \\ \angle{QPR} = 60°$