In triangle pqr,right angle at q and a point s is on pr and a semi circle is drawn on diameter qr touching point s if pq and qs is 35 and 28 respectively then find sr
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there fore the side of sr is 28
because of its taken as radius then d=2r
2r=2*28=56
56 is diameter =qr
r=d/2 =. r=56/2=28
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