In triangle PQR right angle at Q ,PR+ QR = 25cm and PQ =5cm. Determine the values of sin P,cos P and tan A
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Answered by
4
PQ=5cm,PR+QR=25cm
PR=26+QR
IN TRIANGLE PQR, RIGHT ANGLED AT Q,
RP^2=PQ^2+QR^2
(25-QR)^2=5^2+QR^2
625-50QR+RQ^2=25+QR^2
50QR=600
QR=12 cm
PR=13cm
Sin P=P/H=12/13
Cos P=B/H=5/13
Tan P=P/B=5/12
PR=26+QR
IN TRIANGLE PQR, RIGHT ANGLED AT Q,
RP^2=PQ^2+QR^2
(25-QR)^2=5^2+QR^2
625-50QR+RQ^2=25+QR^2
50QR=600
QR=12 cm
PR=13cm
Sin P=P/H=12/13
Cos P=B/H=5/13
Tan P=P/B=5/12
Answered by
5
⚫Sin P=QR/PR=12/13
⚫COS P =PQ/PR =5/13
⚫TAN P =QR /PQ =12/5
⭐hope it will help you well friend your answer in picture
⚫COS P =PQ/PR =5/13
⚫TAN P =QR /PQ =12/5
⭐hope it will help you well friend your answer in picture
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humera4:
thanks
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