Question

In triangle pqr right angle at q 'pr+qr=25cm and pq=5cm. Determine the value of sin p' cosp and tanp

Answer 1

Please see the attachment

Answer 2

Answer:

Step-by-step explanation:

Given —PR+QR=25 and PQ=5.

Let PR be x and QR be 25-x

Then by pthy thm

PR²=PQ²+QR²

x²=(5)²+(25-x)²

x²=25+625+x²-50x

50x=650

x=13

Now PR is 13cm

QR is (25-x)

(25-13)=12

Sin p =12/13

Cos p =15/13

Tan p =12/5.