In triangle PQR right angle at q ,then find the value of side p+r
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Answer:
The value of sin(P+R)=1 .
Given : ∆ PQR is right angled at Q.
i.e. The measure of ∠Q= 90°.
Angle sum property : The sum of all angles in a triangle = 180°
So in Δ PQR , we have
∠P+∠Q+∠R=180° ( By Angle sum property)
⇒ ∠P+90°+∠R=180°
⇒∠P+∠R=180° -90°
⇒∠P+∠R=90°
Now , the value of sin(p+r)=sin(90)=1
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