In triangle PQR right angled at Q. If PQ=12 cm and QR=5cm find sin p
Answers
Answered by
4
In ΔPQR, Right angle is at Q
Given,
PQ = Base = 12 cm
QR = Perpendicular = 5 cm
PR = Hypotenuse = ??
By Pythagoras Theorem
we know that,
(Hypotenuse)² = (Perpendicular)² + (Base)²
PR² = QR² + PQ²
=> PR² = 5² + 12²
=> PR² = 25 + 144
=> PR² = 169
=> PR = √169
PR = 13 = Hypotenuse
Sin θ = Perpendicular/ Hypotenuse
Sin P = 5/13
Similar questions