Math, asked by mehraj1398, 9 months ago

In triangle PQR right angled at Q,PQ =4cm and RQ=3cm find the value of sin p ,sin R ,secP,secR

Answers

Answered by aniket5574
2

Sin P = 3/5

Sin R = 4/5

Sec P = 5/4

Sec R = 5/3

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Answered by diksha9479
2

Step-by-step explanation:

In triangle PQR,

PQ=4cm

QR=3cm

Using Pythagoras theorem,

(PR)²=(PQ)²+(QR)²

(PR)²=(4)²+(3)²

(PR)²=25

PR=5cm

sinP=3/5cm

sinR=4/5cm

secP=5/4cm

secR=5/3cm

Attachments:
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