In triangle PQR right angled at Q,PQ =4cm and RQ=3cm find the value of sin p ,sin R ,secP,secR
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Sin P = 3/5
Sin R = 4/5
Sec P = 5/4
Sec R = 5/3
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Step-by-step explanation:
In triangle PQR,
PQ=4cm
QR=3cm
Using Pythagoras theorem,
(PR)²=(PQ)²+(QR)²
(PR)²=(4)²+(3)²
(PR)²=25
PR=5cm
sinP=3/5cm
sinR=4/5cm
secP=5/4cm
secR=5/3cm
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