Question

In triangle PQR right angled at Q, PQ+QR=25cm and PQ= 5cm . Determine the value of sin p, cos p , tan p.​

Answer 1

Answer:

Step-by-step explanation:

PQ=5cm

⇒PR+QR=25cm

⇒PR=25−QR

Now, In △PQR

⇒(PR)  

2

=PQ  

2

+QR  

2

 

⇒(25−QR)  

2

=5  

2

+QR  

2

 

⇒625+QR  

2

−50QR=25+QR  

2

 

⇒50QR=600

⇒QR=12cm

⇒PR=25−12=13cm

∴sinP=  

PR

QR

​

=  

13

12

​

,cosP=  

PR

PQ

​

=  

13

5

​

,tanP=  

PQ

QR

​

=  

5

12

​

 

Hence, the answers are sinP=  

13

12

​

,cosP=  

13

5

​

,tanP=  

5

12

​

.

Answer 2

Answer:

sinP=12/13

cosP=5/13

tanP=12/5