Question

In triangle pqr Right angled at q pr+qr = 18 pq = 6 determine sin r , tan p

Answer 1

Step-by-step explanation:

pq=6 cm. and pr+qr = 18 cm.

so, 6² + x² = (18 - x)² [ qr = x cm. ]

or, 36 + x² = 324 - 36x + x²

or, 36 + 36x = 324

or, 36(1 + x) = 324

or, 1 + x = 324/36

or, 1 + x = 9

or, x = 8

so, qr = 8 cm.

and, pr = 10 cm.

now,

sin r = pq/pr

= 6/10

= 3/5

tan p = qr/pq

= 8/6

= 4/3