in triangle PQR right_ angled at Q PR+QR= 25 cm & PQ = 5. Determine the values of sinP, cosP &tan P
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1
Answer:
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Answered by
1
Answer:
PQ=5cm
⇒PR+QR=25cm
⇒PR=25−QR
Now, In △PQR
⇒(PR)
2
=PQ
2
+QR
2
⇒(25−QR)
2
=5
2
+QR
2
⇒625+QR
2
−50QR=25+QR
2
⇒50QR=600
⇒QR=12cm
⇒PR=25−12=13cm
∴sinP=
PR
QR
=
13
12
,cosP=
PR
PQ
=
13
5
,tanP=
PQ
QR
=
5
12
Hence, the answers are sinP=
13
12
,cosP=
13
5
,tanP=
5
12
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