Question

In triangle PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the value of cosec P ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

⇒PQ=5cm

⇒PR+QR=25cm

⇒PR=25−QR

Now, In △PQR

⇒(PR)2=PQ2+QR2

⇒(25−QR)2=52+QR2

⇒625+QR2−50QR=25+QR2

⇒50QR=600

⇒QR=12cm

⇒PR=25−12=13cm

∴sinP=PRQR​=1312​,cosP=PRPQ​=135​,tanP=PQQR​=512​

Hence, the answers are sinP=1312​,cosP=135​,tanP=512​.

              I HOPE IT IS HELPFUL