In triangle PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the value of sin P
Answers
Answered by
3
Given PR + QR = 25 , PQ = 5
PR be x. and QR = 25 - x
Pythagoras theorem ,PR2 = PQ2 + QR2
x2 = (5)2 + (25 - x)2
x2 = 25 + 625 + x2 - 50x
50x = 650
x = 13
PR = 13 cm
QR = (25 - 13) cm = 12 cm
sin P = QR/PR = 12/13
cos P = PQ/PR = 5/13
tan P = QR/PQ = 12/5
Similar questions