In triangle PQR right angled at Q, PR+QR=25cm PQ=5cm determine the values of Sin P, Cos P and Tan P
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PR+QR=25
PR is the hypotenuse, PQ and RQ are the legs of the right angled triangle
PQ=5 (given)
Applying Pythagorean theorem we have PR2 - QR2 = PQ2 = 25
(PR2 - QR2)/(PR+QR) = PR-QR = 25/25 = 1
PR+QR = 25
PR-QR = 1
Solving for PR and QR we have PR = 13 and QR = 12
Sin(P) = QR/PR = 12/13
Cos(P) = PQ/PR = 5/13
Tan(P) = QR/PQ = 12/5
PR is the hypotenuse, PQ and RQ are the legs of the right angled triangle
PQ=5 (given)
Applying Pythagorean theorem we have PR2 - QR2 = PQ2 = 25
(PR2 - QR2)/(PR+QR) = PR-QR = 25/25 = 1
PR+QR = 25
PR-QR = 1
Solving for PR and QR we have PR = 13 and QR = 12
Sin(P) = QR/PR = 12/13
Cos(P) = PQ/PR = 5/13
Tan(P) = QR/PQ = 12/5
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Answered by
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Sin P = 12/13
Cos P = 5/13
Tan P = 12/5
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