Question

In triangle pqr right angled at q, qr = 5cm and pr-pq= 1cm. determine the values of sin r, cos r and

Answer 1

Answer:

Given PR + QR = 25 , PQ = 5

PR be x.  and QR = 25 - x 

Pythagoras theorem ,PR2 = PQ2 + QR2

x2 = (5)2 + (25 - x)2

x2 = 25 + 625 + x2 - 50x

50x = 650

x = 13

 

 PR = 13 cm

QR = (25 - 13) cm = 12 cm

sin r = QR/PR = 12/13

cos r = PQ/PR = 5/13

tan r = QR/PQ = 12/5 

Answer 2

Step-by-step explanation:

here is your answer brother