Question

In triangle PQR, right angled at Q, QR=7 cm and PR-PQ= 1 cm. Determine the value of sinP.cosR-sinR.cosP

Answer 1

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Answer 2

Answer:

Explanation:

⇒PQ=5cm

⇒PR+QR=25cm

⇒PR=25−QR

Now, In △PQR

⇒(PR)2=PQ2+QR2

⇒(25−QR)2=52+QR2

⇒625+QR2−50QR=25+QR2

⇒50QR=600

⇒QR=12cm

⇒PR=25−12=13cm

∴sinP=PRQR​=1312​,cosP=PRPQ​=135​,tanP=PQQR​=512​

Hence, the answers are sinP=1312​,cosP=135​,tanP=512​.

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