In triangle pqr S is the midpoint of qr and pt is perpendicular to qr prove that pr 2 is equal to ps 2+qr ×
st +qr upon 2 the whole square
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In triangle pqr S is the midpoint of qr and pt is perpendicular to qr prove that pr 2 is equal to ps 2+qr × st +qr upon 2 the whole square
to Prove pr² = ps² + qr × (st + qr)/2²
pr² = pt² + tr²
pr² = pt² + (sr + st)²
sr = qr/2
=> pr² = pt² + (qr/2 + st)² Eq1
pt² = ps² - st²
putting in eq 1
pr² = ps² - st² + (qr/2 + st)²
=> pr² = ps² + (qr/2 + st)² - st²
using a² - b² = (a+b)(a-b)
a = qr/2 + st and b = st
a+b = (qr +st)/2 and a-b = qr/2
=> pr² = ps² + (qr +st)/2 × qr/2
=> pr² = ps² + qr × (qr +st)/4
=> pr² = ps² + qr × (st + qr)/2²
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