Question

In triangle PQR, see PM in median PM =9 and
PQ^2 +PR^2=290.find the length of QR

Answer 1

Answer:

(PQ)^2 + (PR)^2 = 2(PM)^2 +2(QM)^2

= 290 = 2(9×9)+2(QM)^2

= 290 = 162+2(QM)^2

=290-162 = 2(QM)^2

= 128 = 2(QM)^2

= 128/2 2(QM)^2

= 64 =2(QM)^2

=QM = 8

QR = 2(QM) = 2× 8= 16

Answer 2

Answer:

Step-by-step explanation:

In triangle PQR segment PM is median

:by apologies theorem

PQ^2+PR^2 =2PM^2+2QM^2

290=2 (9)^2+2QM^2

290=2×81+2QM ^2

290=162+2QM^2

2QM^2=290-162

2QM^2=128

QM^2=128/290

QM^2=64

QM=8

QM=1/2QR

8=1/2 QR

QR=8×2

QR=16

Length of QR is 16