Question

In triangle PQR seg PS is bisector of angle QPR. QS =6cm, SR=8 CM, PQ 15cm find PR

Answer 1

Answer: 20cm

Step-by-step explanation:

By theorem of bisector of am angle of a triangle,

PR/PQ = SR/QS

PR/15 = 8/6

6PR = 15×8

6PR = 120

PR = 120/6

PR = 20cm

Answer 2

Answer:

The value of PR will be 20 cm.

Step-by-step explanation:

It is given that in triangle PQR, segment  PS is bisector of angle QPR that is ∠QPS=∠SPR and  QS =6cm, SR=8 CM and PQ 15cm

Using the angle bisector theorem, we get

$\frac{QS}{SR}=\frac{PQ}{PR}$

$\frac{6}{8}=\frac{15}{PR}$

$PR=\frac{15{\times}8}{6}$

$PR=20 cm$

Thus, The value of PR will be 20 cm.