Question

in triangle PQR side QR is produced to S such that angle psr =140 degree, if angle p = angle Q is equal to​

Answer 1

Answer:

the exterior angle is equal to the sum of the two opposite interior angles. p = q = 70. so, the answer to the question is 70.

Answer 2

Answer:

The value of $\angle Q$ is $70$°.

Step-by-step explanation:

Given in $\triangle PQR$ side $QR$ is produced to $S$ such that $\angle PSR=140$°.

Also given $\angle P = \angle Q$.

The angles created between the side of the polygon and the extended adjacent side of the polygon are known as exterior angles. According to the external angle theorem, when a triangle’s side is stretched, the resulting exterior angle is equal to the sum of the measurements of the triangle’s two opposed internal angles.

Here $\angle PSR$ is the exterior angle.

The opposed internal angles are $P,Q$.

From the definition,

$\angle P +\angle Q=\angle PSR$

$\angle Q +\angle Q = 140$

$2\angle Q =140$

$\angle Q=70$.

Therefore, the required angle is $\angle Q=70$°.