In triangle PQR, ST is drawn parallel to QR such that PT : RT = 2 : 3. If O is the point of intersection of QT and RS, then what will be the ratio of the areas of triangle OTS and triangle OQR will be
1. 4 : 25
2. 4 : 9
3. 16 : 25
4. 25 : 4
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1
Answer:
May be the answer 4:9
Step-by-step explanation:
The answer is 4:9
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PT/PR=ST/QR
So,2/5=ST/QR
∆SOT ~ ∆QOR (By AA similarity)
Ar(∆SOT)/Ar(∆QOR)=(ST)²/(QR)²
=4:25
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