Question

in triangle pqr where PQ is equal to PR and QR is extended to a point s and p is joint to S then prove that PS is greater than PQ

Answer 1

in ∆ POR, PR=PQ

therefore angle PRQ= angle PQR

... if 2 sides a triangle are equal then their opposite angles are equal

angle PQS is an exterior angle

therefore angle PQS > angle PRQ

therefore Side PS >PQ

...side opposite to greater angle is greater